Assignment
Objective:
Objective:
To enhance the learning capabilities
of the students about:
of the students about:
· IP SUBNETING
· Internet Protocol Addresses
· CIDR Notation
Uploading
instructions:
instructions:
· Your assignment must be in .doc format (Any other formats
like scan images, PDF, bmp, etc will not be accepted).
like scan images, PDF, bmp, etc will not be accepted).
· Save your assignment with your ID (e.g. bc020200786.doc).
· No assignment will be accepted through email.
Rules for
Marking:
Marking:
It should be clear that your
assignment will not get any credit if:
assignment will not get any credit if:
· The assignment is submitted after due date.
· The submitted assignment does not open or file is corrupted.
· Your assignment is copied from internet, handouts or from
any other student (Strict disciplinary action will be taken in this case).
any other student (Strict disciplinary action will be taken in this case).
Question
1:
[Marks:
06]
1:
[Marks:
06]
a) Calculate the network
address and broadcast address for a LAN having the IP
Address: 210.222.5.121/27
address and broadcast address for a LAN having the IP
Address: 210.222.5.121/27
b) What will be the CIDR
notation when the IP address is 135.1.1.25 and subnet mask is 255.255.248.0?
notation when the IP address is 135.1.1.25 and subnet mask is 255.255.248.0?
Question
2:
[Marks:
09]
2:
[Marks:
09]
Write the subnet bits, default mask
and subnet mask against each of given IP address.
and subnet mask against each of given IP address.
165.2.30.10/29
|
100.1.3.18/18
|
170.222.5.121/28
|
|
Subnet
bits |
|||
Default
mask |
|||
Subnet
mask |
Solution 1:
a) This IP Address: 210.222.5.121/27 belongs to Class C (192 to 223)
· Network address = 210.222.5.96
· Broadcast address = 210.222.5.127
b) CIDR notation: /21
Solution 2:
165.2.30.10/29
|
100.1.3.18/18
|
170.222.5.121/28
|
|
Subnet
bits |
5
|
2
|
4
|
Default
mask |
255.255.0.0
|
255.0.0.0
|
255.255.0.0
|
Subnet
mask |
255.255.255.248
|
255.255.192.0
|
255.255.255.240
|